Man. I'm really torn.
I'm new to the world of photography and I'm looking to add equipment to the camera bag.
I've got the Canon Rebel XT (8mp).
The 75-300 f/4.0-5.6 IS Canon lens
The lens that came with the camera.
And the 580EX Speedlite.
I was looking at 16-35 f/2.8L USM but couldn't bring myself to part with the cash, especially since it would just be "replacing" one of my lenses and no adding to my camer's abilities. So I started looking at Macro lenses (and maybe a macro flash).
My problem is this - I don't entirely know what specifications makes one lens better/different from another.
I know the f/4.0-5.6 references the maximum aperture settings (based on the zoom seetting on the lens)....
And of course I know that the aperture affects the light and depth of field.
So can I assume that the lower the f/ number the larger that lens aperture capablities are... and that this is a "better lens" than those with a higher F/ number (smaller aperture) because more light can get in (although it reduces depth of field)?
Am I over simplifying this?
One more thing...
I thought that you could use the focal length to determine say the zoom on a lens.
I thought the calculation for a 35mm film camera with a 300mm lends would have a calculation something like
300mm / 35mm = 8.6 x zoom. (focal length / sensor size)... sounds reasonable... I think.
Now - when it comes to digital - the sensor is smaller so the calculation changes. I heard the 1.6x factor all the time. This kinda of makes sense. Looking at the Rebel XT sensor of 22.2 x 14.8 you can make the calculation of 35mm / 22.2mm = 1.6. I just love it when numbers make sense don't you? Things like the Fibonacci Sequence and FHI (1.618) just make my heart a flutter ;-) .... But I digress...
Now. If you put a 35mm lens on a 35mm camera - the image should be 1:1 - no wide or zoom right?
Now if you put that same lens on the rebel you should have the following calculation right :
35mm / 22.2mm = 1.6 times zoom right? To get a 1:1 you'd have to have a lens with a focal length of around 22 right?
But when I put the lens that came with the camera on (I believe a 18-55) 22 seems like wide angle (when looking throught the lens). 55 seems to be 1:1 which is reverse to what I was expecting. To get a zoom factor of 1 the formula changes to (35 / sensor size) X 35mm (35 being the size that lenses are engineered to put with) = 56 (focal length) ie 1:1. (I'm rounding numbers)
Have I lost anyone yet? I may have lost myself there.
I admit there seems to be a pattern here with the calculations but I can't figure out the logic behind them.
So if I put a 300mm lens on my Digital Rebel what is the zoom factor?
By the calculation I would have thought focal length / sensor size (300mm / 22m) the zoom is 13.5. Is that correct? If it is, then why is it that the 55mm setting on the other lens looks like a 1x zoom setting but calculates out to be a 2.5x zoom?
Clarification On Lens Calculations
Started by Punky, Apr 07 2005 02:23 PM
2 replies to this topic
#3
Posted 04 May 2005 - 08:22 PM
About calculation, I thing you could read this one
http://www.photograp...p?showtopic=120
and then tell us if something more is wanted
?
Regards,
Herve
http://www.photograp...p?showtopic=120
and then tell us if something more is wanted
Regards,
Herve
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